x^2+4x+16=5

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Solution for x^2+4x+16=5 equation:


Simplifying
x2 + 4x + 16 = 5

Reorder the terms:
16 + 4x + x2 = 5

Solving
16 + 4x + x2 = 5

Solving for variable 'x'.

Reorder the terms:
16 + -5 + 4x + x2 = 5 + -5

Combine like terms: 16 + -5 = 11
11 + 4x + x2 = 5 + -5

Combine like terms: 5 + -5 = 0
11 + 4x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-11' to each side of the equation.
11 + 4x + -11 + x2 = 0 + -11

Reorder the terms:
11 + -11 + 4x + x2 = 0 + -11

Combine like terms: 11 + -11 = 0
0 + 4x + x2 = 0 + -11
4x + x2 = 0 + -11

Combine like terms: 0 + -11 = -11
4x + x2 = -11

The x term is 4x.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4x + 4 + x2 = -11 + 4

Reorder the terms:
4 + 4x + x2 = -11 + 4

Combine like terms: -11 + 4 = -7
4 + 4x + x2 = -7

Factor a perfect square on the left side:
(x + 2)(x + 2) = -7

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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